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Rational Functions

Asymptotes

In this section we will explore asymptotes of rational functions. In particular, we will look at horizontal, vertical, and oblique asymptotes. Keep in mind that we are studying a rational function of the form,

f(x) = P(x)/Q(x),

where P(x) and Q(x) are polynomials. We say that f(x) is in lowest terms if P(x) and Q(x) have no common factors.

1. Horizontal Asymptotes

A. Degree of P(x) < Degree of Q(x)

The rational function f(x) = P(x) / Q(x) in lowest terms has horizontal asymptote
y
= 0 if the degree of the numerator, P(x), is less than the degree of denominator, Q(x). In this case, f(x) → 0 as x → ±∞. An example of a function with horizontal asymptote y = 0 is,

f(x) = x/(x^2 + 1).

B. Degree of P(x) = Degree of Q(x)

The rational function f(x) = P(x) / Q(x) in lowest terms has horizontal asymptote
y = a / b if the degree of the numerator, P(x), is equal to the degree of denominator, Q(x), where a is the leading coefficient of P(x) and b is leading coefficient of Q(x). In this case, f(x) → a / b as x → ±∞. An example of a function with horizontal asymptote y = 1 / 3 is,

f(x) =(x^2 + 1)/(3x^2 + 10x + 7).

C. Degree of P(x) > Degree of Q(x)

The rational function f(x) = P(x) / Q(x) in lowest terms has no horizontal asymptotes if the degree of the numerator, P(x), is greater than the degree of denominator, Q(x).

2. Vertical Asymptotes

The rational function f(x) = P(x) / Q(x) in lowest terms has vertical asymptotes,
x = x1, x = x2, . . . , x = xk, where x1, x2, . . . , xk are roots of Q(x). To find the vertical asymptotes of f(x) be sure that it is in lowest terms by canceling any common factors, and then find the roots of Q(x).

3. Oblique Asymptotes

The rational function f(x) = P(x) / Q(x) in lowest terms has an oblique asymptote if the degree of the numerator, P(x), is exactly one greater than the degree of the denominator, Q(x). You can find oblique asymptotes using polynomial division, where the quotient is the equation of the oblique asymptote. For example, the function,

f(x) - (x^2 -x +2)/(x-3),

has oblique asymptote found by polynomial division,

schematic of the long division problem posed above

Thus, we found that,

f(x) = (x^2 -x +2)/(x-3) = x + 2 + 8/(x-3),

and the equation of the oblique asymptote is the quotient,

y = x + 2.

That is, as |x| gets large, f(x) approaches the line y = x + 2 as depicted in the graph below. Notice that the remainder approaches 0 as |x| → ∞.

graph of the function f(x) = (x^2-x+2)/(x-3).

Finding Asymptotes

When finding asymptotes, it is important to remember that f(x) = P(x) / Q(x) must be in lowest terms. For example, just because x = a is a simple root of Q(x) does not mean that it corresponds to a vertical asymptote. In particular, if x = a is a simple root of P(x) and Q(x) the graph will have a hole at the point x = a. Since a point has no size, a graph of such a function will not look any different when graphed on a calculator. Therefore, we denote a hole in a graph with an open circle. For example, consider the function,

f(x) = (x-1)/(x^2-1).

Notice that we can write Q(x) = x2− 1 as Q(x) = (x − 1)(x + 1). Notice that x = 1 and
x
= −1 are not in the domain of f(x) since they are zeros of Q(x). However, if x ≠ 1 we can cancel the factor x − 1 in the numerator and denominator as,

f(x) = (x-1)/[(x+1)(x-1)] = 1/(x+1), x not equal to 1.

Notice that f(x) and agree everywhere except at the point x = 1 (since x = 1 is not in the domain of f(x), but is in the domain of g(x)). Therefore, the graph of f(x) looks identical to the graph of g(x) except that there is a hole in the graph of f(x) at x = 1 as depicted below.

graph of f(x)=1/(x+1)

 

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In the next section we will explore the graphs of rational functions.

Graphing Rational Functions

The Biology Project > Biomath > Rational Functions > Asymptotes


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April 2006
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