Hill Equation Problem 2 |
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Incorrect!
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Tutorial to help us answer problem 2. | |
| We know that V([S]) is a rational function where the degree of the numerator equals the degree of the denominator because both are degree n. Therefore, when V → a/b, where a and b are the leading coefficients of the numerator and denominator, respectively. In the Hill equation, a = Vmax and b= 1, so we conclude that V → Vmax as [S] → ∞.
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